C++ Institute CPP Exam Actual Questions

What happens when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

int main(){

int t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };

multiset s1(t,t+10);

s1.insert(s1.find(7), 3);

for(multiset::iterator i=s1.begin();i!= s1.end(); i++) {

cout<<*i<<" ";

}

return 0;

}

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What happens when you attempt to compile and run the following code?

#include

#include

using namespace std;

template

class A {

T_v;

public:

A() {}

A(T v): _v(v){}

T getV() { return _v; }

void add(T & a);

void add(string & a);

};

template

void A::add(T & a) { _v+=a; }

void A::add(string & a) {

_v.insert(0, a);

}

int main()

{

Aa("Hello");

string s(" world!");

a.add(s);

cout << a.getV() <

return 0;

}

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What happens when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) { out<

struct Add {

int operator()(int & a, int & b) {

return a+b;

}

};

int main() {

int t[]={1,2,3,4,5,6,7,8,9,10};

vector v1(t, t+10);

vector v2(10);

transform(v1.begin(), v1.end(), v2.begin(), bind1st(1,Add()));

for_each(v2.rbegin(), v2.rend(), Out(cout));cout<

return 0;

}

Program outputs:

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What happens when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

void print(int v) { cout<

struct Sequence {

int start;

Sequence(int start):start(start){}

int operator()() {

return 10*(1+(start++ %3));

}

};

int main() {

vector v1(10);

generate_n(v1.begin(), 10, Sequence(1));

remove(v1.begin(), v1.end(), 10);

for_each(v1.begin(), v1.end(), print);cout<

return 0;

}

Program outputs:

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What will happen when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

int main(){

int t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };

vectorv(t, t+10);

set s1(v.begin(),v.end());

s1.insert(v.begin(),v.end());

pair::iterator,set::iterator> range;

range = s1.equal_range(6);

cout<<*range.first<<" "<<*range.second<

return 0;

}

The output will be:

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